2x+13x^2+25x+14=0

Solution for 2x+13x^2+25x+14=0 equation:

2x+13x^2+25x+14=0

We add all the numbers together, and all the variables

13x^2+27x+14=0

a = 13; b = 27; c = +14;
Δ = b2-4ac
Δ = 272-4·13·14
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-1}{2*13}=\frac{-28}{26}
=-1+1/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+1}{2*13}=\frac{-26}{26}
=-1
$